0=4.9t^2+10t-32.4

Solution for 0=4.9t^2+10t-32.4 equation:

0=4.9t^2+10t-32.4

We move all terms to the left:

0-(4.9t^2+10t-32.4)=0

We add all the numbers together, and all the variables

-(4.9t^2+10t-32.4)=0

We get rid of parentheses

-4.9t^2-10t+32.4=0

a = -4.9; b = -10; c = +32.4;
Δ = b2-4ac
Δ = -102-4·(-4.9)·32.4
Δ = 735.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-\sqrt{735.04}}{2*-4.9}=\frac{10-\sqrt{735.04}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+\sqrt{735.04}}{2*-4.9}=\frac{10+\sqrt{735.04}}{-9.8}
$